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JAMB Mathematics 2019 Paper

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Question : 1

Total: 73

Make q the subject of the formula in the equation

\frac{mn}{a^2} - \frac{pq}{b^2} = 1

$q = \frac{b^2(mn - a^2)}{a^2 p}$
$q = \frac{m^2 n - a^2}{p^2}$
$q = \frac{mn - 2b^2}{a^2}$
$q = \frac{b^2 (n^2 - ma^2)}{n}$

Solution:

$\frac{mn}{a^2} - \frac{pq}{b^2} = 1$

$\frac{mn}{a^2} - 1 = \frac{pq}{b^2}$

$\frac{mn - a^2}{a^2} = \frac{pq}{b^2}$

$pq = \frac{b^2 (mn - a^2)}{a^2}$

$q = \frac{b^2(mn - a^2)}{a^2 p}$

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