Test Index

JAMB Mathematics 2022 Paper

© africaexams.com

Question : 1

Total: 39

Solve for k in the equation

\left(\frac{1}{8}\right)^{k+2}

= 1

2
-4
-2
4

Solution:

$(8^{-1})^{k+2}$ = $(8^{0})$

base 8 cancel out on both sides

-1(k+2) = 0

-k -2 = 0

: k = -2

© africaexams.com

Go to Question:

Next Question