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JAMB Mathematics 2022 Paper

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Question : 1

Total: 39

Solve for k in the equation

\left(\frac{1}{8}\right)^{k+2}

= 1

2
-4
-2
4

Solution:

Concept:

Express both sides as powers of the same base and compare the exponents.

Explanation:

Rewrite

\frac{1}{8}

as

8^{-1}

and

1

as

8^{0}

.

So,

\left(8^{-1}\right)^{k+2} = 8^{0}

.

This gives

8^{-(k+2)} = 8^{0}

.

Since the bases are equal, set the exponents equal:

-(k+2) = 0

.

Simplify:

-k - 2 = 0

.

Therefore,

k = -2

.

Answer:

k = -2

Option C.

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