JAMB Mathematics 2023 Paper

Concept:This problem involves arranging letters when some letters are repeated.Explanation:The word SYLLABUS has 8 letters in total.It contains 2 S's and 2 L's.When identical letters are present, divide by the factorial of each repeated count.So the number of different 8-letter words is:$$\frac{8!}{2! \times 2!}$$This accounts for the two S's and the two L's being indistinguishable.Answer:$$\frac{8!}{2! \, 2!}$$Correct option: C.