Test Index

JAMB Physics 2015 Paper

Question : 1

Total: 66

Solution:

Concept:

The volume of a fixed mass of gas changes with pressure and temperature according to the combined gas law.

Explanation:

Convert temperature to kelvin:

T_1 = 27 + 273 = 300\ \text{K}

and

T_2 = 273\ \text{K}

At S.T.P, pressure is

P_2 = 760\ \text{mmHg}

Use the combined gas law:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

Substitute the given values:

\frac{800 \times 76}{300} = \frac{760 \times V_2}{273}

Rearrange to find

V_2

V_2 = \frac{800 \times 76 \times 273}{760 \times 300}

Simplify and calculate:

V_2 = 72.8\ \text{cm}^3

Answer:

The volume of the gas at S.T.P is

72.8\ \text{cm}^3

. The correct option is C.

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