∠SOR = 2 × 28° = 56° (angle at the centre is twice the angle at the circumference)From ∆SOR|OS| = |OR| (radii)So, ∆SOR is isosceles.
∠ORS = 1800−5602=12402 ( base angles of isosceles triangle are equal)
∴ ∠ORS = 62°
