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BECE Mathematics 2011 Paper

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Question : 35

Total: 40

A length of a ribbon is 16.8 m long. How many ribbons 0.36 m long can be cut from it?

$\;\;0.46$
4.60
46
460

Solution:

\;\;\text{Number of ribbons}\;=\;\frac{\;\text{Length of ribbon}\;}{\;\text{Length to cut}\;}

\;\;\text{Number of ribbons}\;=\;\frac{16.8\ \mathrm{m}}{0.36\ \mathrm{m}}

Change the decimals to whole number

\times 10^{-n}

Where

n

is the number of times to move the decimal point to the right to obtain whole number.

\;16.\overline{8}=168\times 10^{-1}

\;0.\overline{3}\overline{6}=36\times 10^{-2}

\;\;\text{Number of ribbons}\;=\;\frac{168\times 10^{-1}}{36\times 10^{-2}}

\;\;\frac{168}{36}=4.667

Law of division of indices

\;\;\frac{a^{m}}{a^{n}}=a^{m-n}

\;\;\frac{10^{-1}}{10^{-2}}=10^{-1-2}

\;\;\frac{10^{-1}}{10^{-2}}=10^{-1+2}

\;\;\frac{10^{-1}}{10^{-2}}=10^{1}

\;\;\frac{10^{-1}}{10^{-2}}=10

\;\;\text{Number of ribbons}\;=4.667\times 10

\;\;\text{Number of ribbons}\;=46.67

\;\;\text{Number of ribbons}\;\approx 46

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