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BECE Mathematics 2012 Paper

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Question : 23

Total: 40

Given the points

S(5,-2)

T(3,2)

, calculate the gradient of the line

S T

$-2$
$-\;\frac{3}{5}$
$\;\frac{1}{2}$
$2$

Solution:

Concept:

The gradient of a line is the ratio of the change in

Y

to the change in

X

between two points.

Explanation:

For points

S(5,-2)

and

T(3,2)

, let

(X_1,Y_1) = (5,-2)

and

(X_2,Y_2) = (3,2)

.

Gradient formula:

\text{Gradient} = \frac{Y_2 - Y_1}{X_2 - X_1}

Substitute the values:

\text{Gradient} = \frac{2 - (-2)}{3 - 5}

= \frac{2 + 2}{-2}

= \frac{4}{-2} = -2

Answer:

The gradient of line

ST

is

-2

.

Correct option: A.

-2

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