Concept:A vector can be multiplied by a scalar and then subtracted from another vector by performing the operation component-wise.Explanation:We are given r=(4−3) and s=(−31).We need to compute r−2s.First, multiply s by 2:2s=2(−31)=(−62).Now subtract this from r:r−2s=(4−3)−(−62).Subtract the corresponding components:Top component: −3−2=−5.Bottom component: 4−(−6)=4+6=10.Therefore, r−2s=(10−5).This matches option B.Answer:r−2s=(10−5) (Option B).