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BECE Mathematics 2013 Paper

Question : 16

Total: 40

b

Solution:

The triangle above is an isosceles triangle. It has two of its sides equal.

Angles at the base of Isosceles triangle are the same.

a=50^{\circ}

Sum of angles in a triangle is

180^{\circ}

a+50+\text{ angle }PRQ=180

a=50

50+50+\text{ angle }PRQ=180

100+\text{ angle }PRQ=180

Angle

PRQ=180-100

Angle

PRQ=80

The sum of angles on a straight line is

180^{\circ}

Angle

PRQ+b=180

But angle

PRQ=80

80+b=180

b=180-80

b=100

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