BECE Mathematics 2014 Paper

Method IComparing the two sides of equation, 3.14 and 17.5 are at both sides of the equation so you can equate the ones which are not the same.$3p = 18$Divide both sides by 3$p = \; \frac{18}{3} = 6$Method II$(3.14 \times 18) \times 17.5 = 3.14 \times (3p \times 17.5)$The above equation is the same as $3.14 \times 18 \times 17.5 = 3.14 \times 3 \times p \times 17.5$You can solve for the value of $p$ by dividing both sides of the equation by $3.14 \times 3 \times 17.5$$\; p = \; \frac{3.14 \times 18 \times 17.5}{3.14 \times 3 \times 17.5}$$\; p=6.0$Note: 3.14 and 17.5 cancel each other and 3 divides itself once and 18,6 times.