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BECE Mathematics 2014 Paper

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Question : 26

Total: 40

There are 20 identical balls in a box. Twelve are blue and the rest are green. If one ball is taken at random from the box, find the probability that the ball is green.

$\frac{1}{20}$
$\frac{2}{5}$
$\frac{3}{5}$
$\frac{3}{4}$

Solution:

\text{Probability} = \frac{\text{Number of possible selection}}{\text{Total number of samples}}

\text{Total number of samples} = 20

12 \text{ of the balls are blue}

\text{Number of green balls} = 20 - 12 = 8

\text{Number of possible selection of a green ball} = 8

\text{Probability}(\text{Green ball}) = \frac{8}{20} = \frac{2}{5}

Note: 4 divides 8,2 times and 20, 5 times.

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