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BECE Mathematics 2014 Paper
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© africaexams.com
Question : 36
Total: 40
Solve the inequality
2
x
+
10
≥
7
x
2
−
5
2x+10 \geq \frac{7x}{2}-5
2
x
+
10
≥
2
7
x
−
5
x
≤
10
x \leq 10
x
≤
10
x
≥
10
x \geq 10
x
≥
10
x
≤
40
x \leq 40
x
≤
40
x
≥
40
x \geq 40
x
≥
40
Validate
Solution:
2
x
+
10
≥
7
x
2
−
5
2x+10 \geq \frac{7x}{2}-5
2
x
+
10
≥
2
7
x
−
5
Get rid of the fraction by multiplying both sides of the equation by the denominator (2)
2
×
2
x
+
2
×
10
≥
7
x
−
2
×
5
2 \times 2x+2 \times 10 \geq 7x-2 \times 5
2
×
2
x
+
2
×
10
≥
7
x
−
2
×
5
4
x
+
20
≥
7
x
−
10
4x+20 \geq 7x-10
4
x
+
20
≥
7
x
−
10
4
x
−
7
x
≥
−
10
−
20
4x-7x \geq -10-20
4
x
−
7
x
≥
−
10
−
20
−
3
x
≥
−
30
-3x \geq -30
−
3
x
≥
−
30
Divide both sides by -3 . When dividing by a negative the sign changes.
x
≤
−
30
−
3
x \leq \frac{-30}{-3}
x
≤
−
3
−
30
x
≤
10
x \leq 10
x
≤
10
© africaexams.com
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