Find the value of n, if 25.003=(2 × 10)+(5 × 1)+(3 × n)

Correct Answer is : 0.0010.0010.001

Correct Answer is : 0.0010.0010.001

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BECE Mathematics 2015 Paper

Question : 20

Total: 40

n

25.003=(2 \times 10)+(5 \times 1)+(3 \times n)

Solution:

Concept:

A decimal number can be expanded by place value. Here, the digit

3

is after the decimal point, so its place value is

0.001

Explanation:

Given:

25.003 = (2 \times 10) + (5 \times 1) + (3 \times n)

First, compute the whole-number parts:

2 \times 10 = 20

and

5 \times 1 = 5

So,

25.003 = 20 + 5 + (3 \times n)

That means

25.003 = 25 + (3 \times n)

Subtract

25

from both sides:

25.003 - 25 = 3 \times n

0.003 = 3 \times n

Divide both sides by

3

n = \frac{0.003}{3}

Since

0.003 = 3 \times 0.001

, we get:

n = \frac{3 \times 0.001}{3} = 0.001

Answer:

The value of

n

0.001

, which is Option A.

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