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BECE Mathematics 2018 Paper

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Question : 16

Total: 40

In the diagram,

\overline{QP}

\overline{ST}

QPR=68^{\circ}

SRT=40^{\circ}

. Use the information to answer the question below: Find the value of angle

PQR

$40^{\circ}$
$68^{\circ}$
$72^{\circ}$
$108^{\circ}$

Solution:

PARALLEL LINES ANGLE PROPERTIES

VERTICALLY OPPOSITE ANGLES

Vertically opposite angles are the same.

From the above diagram, angle

TRS=

angle

PRQ=40^{\circ}

ANGLES IN A TRIANGLE

Angles in a triangle add up to 180

angle

QPR+

angle

PRQ+

angle

PQR=180

angle

QPR=68^{\circ}

angle

PRQ=40^{\circ}

68+40+PQR=180

108+PQR=180

PQR=180-108

PQR=72^{\circ}

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