Solve the inequality: \;1/2(3x-1)+1 ≤ 7+2x.

Correct Answer is : x≥−13x ≥ -13x≥−13

Correct Answer is : x≥−13x ≥ -13x≥−13

Test Index

BECE Mathematics 2018 Paper

Question : 36

Total: 40

\;\frac{1}{2}(3x-1)+1 \le 7+2x

Solution:

\;\frac{1}{2}(3x-1)+1 \le 7+2x

Get rid of the denominator by multiplying both sides of the equation by the denominator, 2

\;2 \times \;\frac{1}{2}(3x-1)+2 \times 1 \le 2 \times 7+2 \times 2x

\;3x-1+2 \le 14+4x

\;3x+1 \le 14+4x

\;3x-4x \le 14-1

\;-x \le 13

Divide both sides by -1 . When dividing by a negative, the inequality sign changes direction.

\;\frac{-x}{-1} \ge \;\frac{13}{-1}

\;x \ge -13

Go to Question:

Prev Question

Next Question