Same as 10−(x+3)∕2=8 Same as 10−1(x+3)∕2=8 10−1(x+3)∕2=8 Get rid of the fraction by multiplying each side of the equation by the LCM of the denominators The denominators are 1,2 and 1 and their LCM is 2 NOTE:10 = 10/1 and 8=8∕1, thus every number has one dividing it but its not written ‌⇒10−1(x+3)∕2=8 ‌2×10−1×2(x+3)∕2=8×2 ‌20−1(x+3)=16 Applying a(b+c)=a×b+a×c ‌⇒−1(x+3)=−1xx−1×3=−x−3 ‌20−1(x+3)=16 ‌⇒20−x−3=16 Making sure x is at one side of the equation, ‌−x=16+3−20 ‌−x=−1 Divide both sides by -1 ⇒x=1 Divide both sides by -1 ⇒x=1 NOTE: You can as well move x to the right size of the equation and 16 to the left and the answer will still be the same.Thus, ‌20−x−3=16 ‌20−3−16=x ‌20−19=x ‌1=x