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BECE Mathematics 2020 Paper

Question : 12

Total: 40

(x-3)^2=16

x

Solution:

Concept:

Solving a squared linear equation using the square root method.

Explanation:

Start with the given equation:

(x-3)^2=16

Take the square root of both sides:

\sqrt{(x-3)^2}=\sqrt{16}

Since we need the positive value of

x

, we consider only the positive square root:

x-3=\sqrt{16}

\sqrt{16}=4

So:

x-3=4

Add

3

to both sides:

x=4+3

x=7

Answer:

The positive value of

x

7

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