Concept:Use the distributive property to multiply each term in the first bracket by each term in the second bracket.Solution:Expand (a−2)(2a+3) by distribution.(a−2)(2a+3)=a(2a+3)−2(2a+3)a(2a+3)=2a2+3a−2(2a+3)=−4a−6Add the results: 2a2+3a−4a−6Combine like terms: 3a−4a=−aSo, (a−2)(2a+3)=2a2−a−6Answer:Option C (2a2−a−6)