Concept:A translation moves every point by the same vector. If P is moved by r=(ba) to P′, then P′=P+r, so the vector is r=P′−P (image minus original).Given:Original point P(10,−3), image P′(4,5)Solution:Subtract the coordinates of P from those of P′:x-component: 4−10=−6y-component: 5−(−3)=5+3=8r=(8−6)Check: P+r=(10+(−6),−3+8)=(4,5)=P′ ✓Key point: Subtracting the other way (P−P′) gives (−86) (option B), which is the vector that moves P′ back to P.Answer:Option C ((8−6))