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BECE Mathematics 2023 Paper

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Question : 27

Total: 40

Simplify:

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10}

$\frac{1}{10}$
$\frac{3}{20}$
$\frac{1}{5}$
$\frac{3}{5}$

Solution:

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10}

Change the mixed fraction to improper fraction.

1\frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{2+1}{2} = \frac{3}{2}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \left(\frac{3}{2} - \frac{5}{6}\right) \times \frac{9}{10}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \left(\frac{3 \times 3 - 1 \times 5}{6}\right) \times \frac{9}{10}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \left(\frac{9-5}{6}\right) \times \frac{9}{10}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \left(\frac{4}{6}\right) \times \frac{9}{10}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \frac{4}{6} \times \frac{9}{10}

Note: 2 divides 4, 2 times and 6, 3 times

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \frac{2}{3} \times \frac{9}{10}

Note: 2 divides itself once and 10, 5 times. 3 divides itself once and 9,3 times

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \frac{1}{1} \times \frac{3}{5}

\left(1\frac{1}{2} - \frac{5}{6}\right) \times \frac{9}{10} = \frac{3}{5}

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