Test Index

BECE Mathematics 2024 Paper

© africaexams.com

Question : 13

Total: 40

A hawker is carrying a basket load of three types of fruits: oranges, mangoes and pears. If

\; \frac{2}{5}

of the fruits are oranges and

\; \frac{6}{25}

mangoes, what percentage of the fruits are pears?

$9 \%$
$18 \%$
$64 \%$
$36 \%$

Solution:

Concept:

The sum of the fractions of all fruit types is

1

, which represents

100\%

.

Explanation:

Fraction of oranges

= \frac{2}{5}

and fraction of mangoes

= \frac{6}{25}

.

Fraction of pears

= 1 - \left( \frac{2}{5} + \frac{6}{25} \right)

.

Convert

\frac{2}{5}

to a denominator of

25

:

\frac{2}{5} = \frac{10}{25}

.

So, fraction of pears

= 1 - \left( \frac{10}{25} + \frac{6}{25} \right)

.

That gives

1 - \frac{16}{25} = \frac{9}{25}

.

Convert

\frac{9}{25}

to a percentage:

\frac{9}{25} \times 100\% = 36\%

.

Answer:

Percentage of pears

= 36\%

.

Correct option: D.

36\%

.

© africaexams.com

Go to Question:

Prev Question

Next Question