BECE Mathematics 2024 Paper

Steps to find equation of a line1. Find the gradient/slope of the line2. Use the point $(x, y)$ and any known point on the line to calculate the slope/gradient3. Equate the expression in step 2 to the calculated gradient/slope in step 14. Make $y$ the subject of the equation in step 3$\;\text{Slope/Gradient}\;=\;\frac{\;\text{Change in}\;Y}{\;\text{Change in}\;X}=\;\frac{Y_2-Y_1}{X_2-X_1}$Pick any two points on the straight line to calculate the slope.Using (1,1) and ( 0,3 )$\;Y_2=3$$\;Y_1=1$$\;X_2=0$$\;X_1=1$ Slope/Gradient $=\;\frac{3-1}{0-1}=\;\frac{2}{-1}=-2$Using the point $(x, y)$ and $(1,1)$$\;\frac{y-1}{x-1}=-2$Every number is being divided by 1.$\;-2=\;\frac{-2}{1}$$\;\;\frac{y-1}{x-1}=\;\frac{-2}{1}$Cross multiply$\;1 \times (y-1)=-2 x(x-1)$$\;y-1=-2 x+2$$\;y=-2 x+2+1$$\;y=-2 x+3$