Make m the subject of the relation \;1/m = \;1/p + \;1/r.

Correct Answer is : m= prr+pm = \;pr/r + pm=r+ppr

Correct Answer is : m= prr+pm = \;pr/r + pm=r+ppr

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BECE Mathematics 2024 Paper

Question : 26

Total: 40

Make

m

\;\frac{1}{m} = \;\frac{1}{p} + \;\frac{1}{r}

Solution:

\;\frac{1}{m} = \;\frac{1}{p} + \;\frac{1}{r}

Get rid of the fractions by multiplying both sides of the equation by the L.C.M of the denominators. The L.C.M of

m, p

and

r

m \times p \times r

m \times p \times r \times \frac{1}{m} = m \times p \times r \times \frac{1}{p} + m \times p \times r \times \frac{1}{r}

Cancel out

\;p \times r \times 1 = m \times r \times 1 + m \times p \times 1

\;p r = m r + m p

Factorize

m

out

p r = m (r + p)

Divide both sides by

r + p

m = \;\frac{pr}{r + p}

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