Make m the subject of the relation \;1/m = \;1/p + \;1/r.

Correct Answer is : m= prr+pm = \;pr/r + pm=r+ppr

Correct Answer is : m= prr+pm = \;pr/r + pm=r+ppr

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BECE Mathematics 2024 Paper

Question : 26

Total: 40

Make

m

\;\frac{1}{m} = \;\frac{1}{p} + \;\frac{1}{r}

Solution:

Concept:

Rearranging an equation involving reciprocals by using the least common multiple to eliminate fractions.

Explanation:

Start with the given relation:

\frac{1}{m} = \frac{1}{p} + \frac{1}{r}

To remove the fractions, multiply both sides by the product

m p r

m p r \times \frac{1}{m} = m p r \times \frac{1}{p} + m p r \times \frac{1}{r}

Cancel common factors in each term:

p r = m r + m p

Factor

m

out of the right-hand side:

p r = m(r + p)

Divide both sides by

(r + p)

to isolate

m

m = \frac{pr}{r + p}

Answer:

m = \frac{pr}{r + p}

This matches option A.

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