BECE Mathematics 2024 Paper

Concept:The intersection $P \cap Q$ is the set of elements that belong to both $P$ and $Q$.Solution:In the diagram, circle $Q$ lies completely inside circle $P$.Elements inside $Q$: $c, d, e$, so $Q = \{c, d, e\}$.Elements inside $P$ (including those inside $Q$): $a, b, c, d, e$, so $P = \{a, b, c, d, e\}$.The elements common to both sets are $c, d, e$.$P \cap Q = \{c, d, e\}$Key point: When $Q$ is a subset of $P$ ($Q \subset P$), $P \cap Q = Q$. The elements $f, g, h$ are only in $U$.Answer:Option A ({c, d, e})