BECE Mathematics 2025 Paper

Concept:Solve an inequality like an equation: expand brackets, collect $x$ terms on one side and numbers on the other. The sign reverses only when you multiply or divide by a negative number.Solution:Expand the left side: $3(x - 5) = 3x - 15$Expand the right side: $15 - 4(8 - x) = 15 - 32 + 4x = 4x - 17$ (note $-4 \times -x = +4x$)The inequality becomes $3x - 15 > 4x - 17$Add $17$ to both sides: $3x + 2 > 4x$Subtract $3x$ from both sides: $2 > x$Read from the $x$ side: $x < 2$Key point: Keeping $x$ on the side where its coefficient is larger avoids dividing by a negative number, so the sign never has to flip.Answer:Option C ($x < 2$)