BECE Mathematics 2026 Paper

Concept:Probability of an event = $\dfrac{\text{number of favourable outcomes}}{\text{total number of possible outcomes}}$.Solution:Letters of HAPPY: H, A, P, P, Y. Each of the 5 letters is equally likely to be picked, so total outcomes $= 5$.Favourable outcomes (letter P): the word has two P's, so favourable outcomes $= 2$.$P(\text{P}) = \dfrac{2}{5}$Key point: Count each P separately; counting P only once would give $\dfrac{1}{5}$ (option A), which is wrong.Answer:Option C ($\frac{2}{5}$)