BECE Mathematics 2026 Paper

Concept:To make $y$ the subject, undo the operations around $y$ one at a time, doing the same thing to both sides.Solution:$p = \dfrac{r - 4y}{3}$Multiply both sides by $3$ to clear the fraction:$3p = r - 4y$Add $4y$ to both sides and subtract $3p$ from both sides, so the $y$ term is positive:$4y = r - 3p$Divide both sides by $4$:$y = \dfrac{r - 3p}{4} = \dfrac{1}{4}(r - 3p)$Key point: Option A, $\frac{1}{4}(3p - r)$, has the signs reversed; it would come from forgetting that $-4y$ is negative.Answer:Option B ($y=\frac{1}{4}(r-3p)$)