BECE Mathematics 2026 Paper

Concept:Multiply each vector by its scalar, then add component-wise.Solution:Given $a=\binom{3}{1}$ and $b=\binom{-2}{1}$.First, compute $6b$:$$6b = 6\binom{-2}{1} = \binom{-12}{6}$$Then, compute $2a$:$$2a = 2\binom{3}{1} = \binom{6}{2}$$Now add the results:$$6b + 2a = \binom{-12}{6} + \binom{6}{2} = \binom{-12+6}{6+2} = \binom{-6}{8}$$Answer:Option B ($\binom{-6}{8}$)