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JAMB Chemistry 2011 Paper

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Question : 5

Total: 47

The relative atomic mass of a naturally occurring lithium consisting of 90%

{}^7_3

{}^6_3

10% Li is

6.9
7.1
6.2
6.8

Solution:

R.A.M = m $_{1} \alpha_{1}$ + m $_{2} \alpha_{2}$

= 7(90/100) + 6(10/100)

= 6.3 + 0.6

= 6.9

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