From the diagram above, find the amount of solute deposited when 200 cm3{}^33 of the solution is cooled from 55°C to 40°C.
From the diagram,
55°C = 7 moles; 40°C = 6 moles.
Amount of solute deposited = 7 - 6 = 1 mole.
1000 cm3{}^33 = 1 mole
200 cm3{}^33 = x
x = 200×11000\frac{200 \times 1}{1000}1000200×1
= 0.20 mole.
