Let the relative abundance of the energy with mass 37 beTotal relative abundance of the isotope of mass 359100-k)Total mass of isotope of mass 37-37x, while that of 35-359(100x)-37x + 3500 − 35 − 35.5-37x + 3500 − 35n − 35.5Mean mass of chlorine atom − (2n + 3500)/ ÷ 100= 35.52x + 3500 − 3550yx = 50/2