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JAMB Chemistry 2017 Paper

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Question : 43

Total: 49

Calculate the amount in moles of a gas which occupies 10.5 dm3 at 6 atm and 30oC [R = 0.082 atm dm3 K-1 mol-1]

2.536
1.623
4.736
0.394

Solution:

For an ideal gas PV = nRT

Amount in moles = n

Volume v = 10.5dm3

Pressure P = 6atm

Temperature T = 30°C + 273 = 303k

R, Gas constant = 0.082 atmdm3k-1 mol

Recall from ideal gas equation

pv = nRT

n =

\frac{RV}{RT}

n =

\frac{6 \times 10.5}{0.082 \times 303}

n= 2.536mol

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