Test Index

JAMB Chemistry 2018 Paper

© africaexams.com

Question : 51

Total: 87

What mass of Cu would be produced by the cathodic reduction of Cu

^{2+}

when 1.60A of current passes through a solution of CuSO

_{4}

for 1 hour. (F=96500Cmol

^{-1}

, Cu=64)

7.64g
3.82g
1.91g
0.96g

Solution:

M = $\frac{MmIT}{96500n}$

Where

M=mass

Mm = Molar mass = 64g/mol

I = current = 1.6A

T= Time =1h r=3600s

N= No of Charge = +2

M = $\frac{64x \times 1.6 \times 3600}{96500 \times 2}$

M=1.91g

© africaexams.com

Go to Question:

Prev Question

Next Question