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JAMB Chemistry 2018 Paper

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Question : 58

Total: 87

The hydrogen ion concentration of a sample of orange juice is 2.0 X 10

^{-11}

^{-3}

. What is its p

^{OH}

? [log102 = 0.3010]

3.30
13.00
10.70
11.30

Solution:

PH+POH=14

p

^{H}

= Log [H

^+

]

p[H $^+$ ] = 2.0 X 10 $^{-11}$ moldm $^{-3}$

p $^{H}$ = Log [2.0 X 10 $^{-11}$ ]

p $^{H}$ = 10.70

10.70+ p $^{OH}$ =14

p

^{OH}

= 14 -10.70

= 3.30

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