JAMB Chemistry 2019 Paper

Parameters given:

V$_{1}$ = 200 cm$^{3}$; T$_{1}$ = 27 + 273 = 300K.

V$_{2}$ = 150 cm$^{3}$; T$_{2}$ = ?

P$_{2}$ = 2P$_{1}$.

Using the Ideal Gas Equation:

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

$\frac{P_1 \times 200}{300} = \frac{2P_1 \times 150}{T_2}$

$\frac{2}{3} = \frac{300}{T_2}$

T$_{2}$ = 450K.

= 450K - 273K

= 177°C

177 - 27 = 150

That is the amount by which T1 must be increased.