Ammonium nitrite = NH4_44NO2_22
NH4+_4^+4+: Let the oxidation number of Nitrogen = x
x + 4 = 1 ⟹ \implies⟹ x = 1 - 4
x = -3
NO2−_2^-2−: x - 4 = -1
x = -1 + 4 ⟹ \implies⟹ x = +3.
The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.
