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JAMB Chemistry 2019 Paper

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Question : 68

Total: 80

The velocity, V of a gas is related to its mass, M by (k = proportionality constant)

V = $\frac{k}{M}$
V = $\frac{k}{M^{\frac{1}{2}}}$
V = $kM^2$
V = $\left(\frac{k}{M}\right)^{\frac{1}{2}}$

Solution:

Recall:

V = $\sqrt{\frac{3RT}{M}}$

$\therefore V \propto \frac{1}{\sqrt{M}}$

$V = \frac{k}{\sqrt{M}}$

V = $\frac{k}{M^{\frac{1}{2}}}$

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