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JAMB Chemistry 2019 Paper

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Question : 77

Total: 80

An element Z contains 80% of

{}^{16}_{8}

{}^{18}_{8}

Z. Its relative atomic mass is

16.2
17.6
16.0
16.4

Solution:

R.A.M of Z = $16\left(\frac{80}{100}\right) + 18\left(\frac{20}{100}\right)$

= $12.8 + 3.6$

= 16.4

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