JAMB Chemistry 2023 Paper

Concept:Faraday’s constant is the electric charge carried by one mole of electrons.Explanation:During electrolysis, the amount of charge needed to deposit or liberate one mole of substance is measured by Faraday’s constant.It is calculated as the charge of one mole of electrons.One electron has a charge of about $1.602 \times 10^{-19}\,\mathrm{C}$.Multiplying this by Avogadro’s number, $6.022 \times 10^{23}\,\mathrm{mol^{-1}}$, gives:$$F = (1.602 \times 10^{-19}\,\mathrm{C}) \times (6.022 \times 10^{23}\,\mathrm{mol^{-1}})$$$$F \approx 96,485\,\mathrm{C/mol}$$Therefore, Faraday’s constant is $96,485\,\mathrm{C/mol}$.Answer:D. $96,485\,\mathrm{C/mol}$