According to the Ideal gas equation, PV = nRT
Given: P = 1.58 atm, V = ?, n = 1 mole, R = 0.082, T= 13 + 273K = 286K
Substituting all the given parameters,
V = nRTP\;\frac{nRT}{P}PnRT
V = 1×0.082×2861.58\;\frac{1\times 0.082\times 286}{1.58}1.581×0.082×286
V = 14.84 dm3^33