Oxidation state of S in H2S = 0
H = +1, (+1 X 2) + S = 0
+ 2 + S = 0
S = - 2 ( from the reactant)
Already, from the equation, S is in solid form,as an element, therefore the oxidation state of elements in their free state is 0
The change in oxidation state of sulphur is from - 2 to 0
