Solubility = Amount of solute dissolved in 1dm3^{3}3 of solvent divided by the volume of solvent
Solubility = massmolar mass\;\frac{\text{mass}}{\text{molar mass}}molar massmass x 1 dm3^{3}3
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Solubility = 12758.5\;\frac{127}{58.5}58.5127 x 1 dm3^{3}3
= 2.17
= 2.2 moldm−3^{-3}−3
