Empirical formula x n = Molecular mass
(CH3_33 ) X n = 30 ; Given that C = 12, H = 1
[ 12 + (1x3) ] n = 30
15n = 30
n = 3015\; \frac{30}{15}1530
n = 2.
Molecular formula = (CH3_33 ) X n = (CH3_33 ) X 2 = C2_22H6_66