If p : q = 23 : 56, then the sum S1 of ratio = 23 + 56 = 96 If q : r = 34 : 12, then the sum S2 of ratio = 34 + 12 = 54 Let p + q = T1, then q = (56÷96)T1 = (56×69)T1 = 59T1 Again, let q + r = T2, then q = (34÷54)T2 = (34×45)T2 = 35T2 Using q = q 59T1 = 35T2 5 x 5T1 = 9 x 3T2 T1T2 = 9×35x5 = 2725 Giving that, T1 = 27 and T2 = 25 P = (23÷S1)T1 = (23÷96)T1 = (23×69)27 = 12 q = (56÷S1)T1 = (56÷96)T1 = (56×69)27 = 15 and r = (12÷S2)T2 = (12÷54)T2 = (12×45)25 = 10 Hence p : q : r = 12: 15 : 10