27x+2÷9x+1=32x27^{x+2} \div 9^{x+1} = 3^{2x}27x+2÷9x+1=32x
33(x+2)÷32(x+1)=32x3^{3(x+2)} \div 3^{2(x+1)} = 3^{2x}33(x+2)÷32(x+1)=32x
33x+6÷32x+2=32x3^{3x+6} \div 3^{2x+2} = 3^{2x}33x+6÷32x+2=32x
∴(3x+6)−(2x+2)=2x\therefore (3x+6) - (2x+2) = 2x∴(3x+6)−(2x+2)=2x
x+4=2x ⟹ x=4x+4 = 2x \implies x = 4x+4=2x⟹x=4