Integrate {1+x}{x³} dx

Correct Answer is : −12x2−1x+k- {1}{2x²} - 1/x + k−2x21−x1+k

Correct Answer is : −12x2−1x+k- {1}{2x²} - 1/x + k−2x21−x1+k

Test Index

JAMB Mathematics 2013 Paper

Question : 46

Total: 47

Integrate

\frac{1+x}{x^{3}} dx

Solution:

$\int \frac{1+x}{x^{3}} dx$

= $\int \left( \frac{1}{x^{3}} + \frac{x}{x^{3}} \right) dx$

= $\int (x^{-3} + x^{-2}) dx$

= $\frac{-1}{2x^{2}} - \frac{1}{x} + k$

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