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JAMB Mathematics 2014 Paper

Question : 22

Total: 47

\begin{vmatrix} 0 & 3 & 2 \\ 1 & 7 & 8 \\ 0 & 5 & 4 \end{vmatrix}

Solution:

$0 \begin{vmatrix} 7 & 8 \\ 5 & 4 \end{vmatrix} -3 \begin{vmatrix} 1 & 8 \\ 0 & 4 \end{vmatrix} +2 \begin{vmatrix} 1 & 7 \\ 0 & 5 \end{vmatrix}$

= 0(28 - 40) - 3(4 - 0) + 2(5 - 0)

= 0(-12) - 3(4) + 2(5)

= 0 - 12 + 10

= -2

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