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JAMB Mathematics 2014 Paper

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Question : 45

Total: 47

in the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)?

y = x + 5
y = -x + 5
y = x - 5
y = -x - 5

Solution:

(x1, y1) = (0,5)

(x2, y2) = (5, 0)

Using

\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}

\frac{y - 5}{0 - 5} = \frac{x - 0}{5 - 0}

\frac{y - 5}{-5} = \frac{x}{5}

5(y - 5) = -5x

y - 5 = -x

x + y = 5

y = -x + 5

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