[1 ÷ (x+1)] + [1 ÷ (x − 1)] = ((x − 1) + [(x + 1)) ÷ (x+1)(x − 1)] Using the L.C.M. = (x − 1 + x + 1) ÷ (x + 1)(x − 1) = (x + 2 − 1 + 1) ÷ (x + 1)(x − 1) = 2x ÷ (x + 1)(x − 1) =2x ÷ (x + 1)(x − 1)