Evaluate (cos4x + sin3x)dx

Correct Answer is : 141/441sin4x - 131/331cos3x + k

Correct Answer is : 141/441sin4x - 131/331cos3x + k

Test Index

JAMB Mathematics 2016 Paper

Question : 12

Total: 50

Evaluate

\int

(cos4x + sin3x)dx

Solution:

$\int(\cos 4x + \sin 3x) dx$

= $\frac{1}{4}\sin 4x - \frac{1}{3}\cos 3x + k$

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